Resolução:
$\;\sqrt{3}\,=\,\sqrt[\large 2]{3^{\large 1}}\,$ $=\,\sqrt[\large 2 \centerdot 3]{3^{1\centerdot 3}}\,=\,\sqrt[\large 6]{3^{\large 3}}\,=\,\sqrt[\large 6]{27}\;$
$\;\sqrt[\large 3]{5}\,=\,\sqrt[\large 3]{5^{\large 1}}\,$ $=\,\sqrt[\large 2 \centerdot 3]{5^{1\centerdot 2}}\,=\,\sqrt[\large 6]{5^{\large 2}}\,=\,\sqrt[\large 6]{25}\;$
Resposta: