(MED SANTO ANDRÉ) Simplificando a expressão $\phantom{X}\dfrac{2^{\large n+4}\,-\,2\,\centerdot \,2^{\large n}}{2\, \centerdot\, 2^{\large n+3}}\phantom{X}$ obtém-se:
a)
$\,2^{\large n+1} - \dfrac{1}{8}\,$
c)
$\,-\,2^{\large n+1}\,$
d)
$\,1\,-\,2^{\large n}\,$
