resposta:
Resolução:
$\phantom{X}A_{base}\,=\,5^2\,=\,25\,cm^2\phantom{X}$
$\phantom{X}H\,=\,3\,cm\phantom{X}$
$\phantom{X}V\,=\,\dfrac{\,A_{base}\,\centerdot\,H\,}{3}\,=\,\dfrac{\,25\,\centerdot\,3\,}{3}\,=\,25\,cm^3\phantom{X}$
resposta:
V = 25 cm³
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