resposta:

CÁTODO$\,\left\{\begin{array}{rcr} Cu^{++}&\, + \,2e^{-}\;\rightarrow\;Cu^{o}\\ H^{+}\phantom{X}\,& \\ \end{array} \right.\,$

ÂNODO$\,\left\{\begin{array}{rcr} NO_{3}{}^{-} & \\ 2OH^{-}\,&\rightarrow\;\frac{\;1\;}{2}O_{2}\, + \,H_{2}O\,+ \,2e^{-}\, \\ \end{array} \right.\,$

Cu(NO₃)₂ aquoso produz Cu^o no cátodo e O₂ no ânodo.

CÁTODO$\,\left\{\begin{array}{rcr} Cu^{++}&\, + \,2e^{-}\;\rightarrow\;Cu^{o}\\ H^{+}\phantom{X}\,& \\ \end{array} \right.\,$

ÂNODO$\,\left\{\begin{array}{rcr} 2Br^{-}\,&\rightarrow\;Br_{2}\, + \,2e^{-}\, \\OH^{-}\, & \\ \end{array} \right.\,$

CuBr₂ aquoso produz Cu^o no cátodo e Br₂ no ânodo.

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